Archive for The Weekly Challenge
{ November 6, 2009 @ 1:27 pm }
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{ Solution, Uncategorized }
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The Answer :
1 = (5 / 5) x (5 / 5),
2 = (5 / 5) + (5 / 5),
3 = (5 + 5 + 5) / 5,
4 = ((5 x 5) – 5) / 5,
5 = ((5 – 5) / 5 ) + 5,
6 = ((5 x 5) + 5) / 5,
7 = 5 + ((5 + 5) / 5),
8 = (5 – (5 / 5)) / .5,
9 = 5 + 5 – (5 / 5),
10 = 5 + 5 x (5 / 5).
The Winners :
The First
Mohamed Wagdy
The Second
abdullah-adel
The Third
EnasMohey
Then
- 4@
- ahmed said
- Mohammad Rashad
- Shohanda
- Ghada Abdelbaset
- Mohamed Mostafa
And now winners who have simple errors :
- Abu-Bakr Taha
- Muhammad Albedewy
- Omar Mohammad Othman
- sara el_sebaiee
- Ahmed Hussam
- Aya Magdy
- karim ibrahim
- abumuslimamr
- bino
- abdullahnajuib
- Esraa Ibrahim
- Salma H. E. Mostafa
- yasmeena2090
- Ahmed Magdy
Thank you all
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{ October 31, 2009 @ 12:28 pm }
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{ Problem }
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Using standard mathematical symbols, e.g. +, -, x, etc., rearrange (4) fives to equal the numbers one to ten. For example, 5/5 + 5 – 5 = 1, 5/5 + 5/5 = 2, etc.
Note : you can use decimal point (.) only once.
{ October 29, 2009 @ 11:55 pm }
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{ Solution }
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Answer :

to

The Winners:
The First
Noran
The Second
bino
The Third
EnasMohey
Then
- khaled ahmed
- New
- mona
- Hebatalla
- abdullah adel
- Aya Magdy
{ October 23, 2009 @ 11:00 pm }
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{ Problem }
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Below are 10 skittles in an upside-down triangle shape, can you move the skittles around such that the triangle is the correct way up? You can move any skittle left or right, but, at most, you are only allowed to move three skittles up or down!

{ October 18, 2009 @ 3:30 pm }
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{ Solution }
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Answer:
0: since one of the terms is (x – x).
The Winners
The First
EnasMohey
The Second
Haytham Alaa
The Third
Hebatalla
Then
- marmoor1989
- Noran
- Aya Magdy
- nabil
- khaled ahmed
- the sergeon
{ October 11, 2009 @ 7:07 am }
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{ Problem }
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What does this equation simplify to?
(x – a) * (x – b) * (x – c) * … * (x – z) = ?
{ October 3, 2009 @ 5:52 pm }
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{ Solution }
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Answer

Using Pythagoras’ Theorem:
for the right-angled triangle in the figure
(r – a)2 + (r – b)2 = r2
Now, a = 6 cm and b = 12 cm. So,
(r – 6)2 + (r – 12)2 = r2 or
r2 – 2(6)r + 62 + r2 – 2(12)r + 122 = r2. This simplifies to
r2 – 36r + 180 = 0. On factorizing, we get
(r – 30)(r – 6) = 0.
Thus, the radius of the circle is 30 cm.
Area = 30 * 30 * pi.
The Winners:
The First
Eman Fateen
The Second
New
The Third
Rana
then
- Mohamed Osama
- Rana M
- EnasMohey
- Aya Magdy
- Hebatalla
- Amr Saqr
- Nora Youssef
{ September 26, 2009 @ 10:36 am }
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{ Problem }
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In the above figure, the rectangle at the corner measures 6 cm x 12 cm. What is the area of the circle?
{ September 7, 2009 @ 4:12 am }
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{ Solution }
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Answer:
21 hours and 36 minutes. The exact size of the pipes and reservoir does not matter. If we label the large pipes L, the small pipes S and if the reservior has a total of T litres, then:
T / 6L = 12 which means L = T / 72
and
T / (3L + 9S) = 8 which means that S = T / 108
we want
T / 5S which gives 108 / 5 hours = 21.6 hours = 21 hours and 36 minutes.
The Winners:
The First
EnasMohey
The Second
Hebatalla
The Third
Shreif Hassan
{ August 29, 2009 @ 6:13 pm }
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{ Problem }
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A large fresh water reservoir has two types of drainage system. Small pipes and large pipes. 6 large pipes, on their own, can drain the reservoir in 12 hours. 3 large pipes and 9 small pipes, at the same time, can drain the reservoir in 8 hours. How long will 5 small pipes, on their own, take to drain the reservoir?
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